题目如下：

A boomerang is a set of 3 points that are all distinct and not in a straight line.

Given a list of three points in the plane, return whether these points are a boomerang.

 

Example 1:

Input: [[1,1],[2,3],[3,2]]Output: true

Example 2:

Input: [[1,1],[2,2],[3,3]]Output: false

 

Note:

1. points.length == 3
2. points[i].length == 2
3. 0 <= points[i][j] <= 100

解题思路：本题就是判断三点是否在一条直线上，判断的方法也很简单，任意从这三个点中选取两组点对，如果这两组的点对的斜率相同，则在同一直线上。

代码如下：

class Solution(object):    def isBoomerang(self, points):        """        :type points: List[List[int]]        :rtype: bool        """        return (points[0][1]-points[1][1]) * (points[1][0]-points[2][0]) \               != (points[0][0]-points[1][0]) * (points[1][1]-points[2][1])